How many odd 4 digit positive integers that are multiples of 5 can be formed without using the digit 3?
Correct Answer : Choice D. 648
Following conditions are stated
1. The number is a 4 - digit number.
2. It is an odd number.
3. It is a multiple of 5.
4. 3 cannot be a digit in the number.
Combining conditions 2 and 3, we can conclude that the unit digit is 5. Therefore, the unit digit has only one option.
The thousands place, the left most digit cannot be 0. It also cannot be 3. So, it has 8 options.
The hundreds place cannot be 3. So, it has 9 options.
The tens place cannot be 3. So, it has 9 options.
Therefore, there are 8 * 9 * 9 * 1 = 648 numbers.
Labels: GMAT Counting Methods, GMAT Number Properties, GMAT Numbers, GMAT Permutation Combination, GMAT Problem Solving, GMAT Problem Solving Practice