Any n-sided convex polygon with more than 3 sides will have n(n-3)/2 diagonals.
For instance, let us look at a square. A square has 4 sides and 2 diagonals. Let us apply this formula with n = 4.
We get 4(4-3)/2 = 2 diagonals.
Here is a question on finding the number of diagonals.
If a n-sided convex polygon has 14 diagonals, how many sides does the polygon have?
Any n-sided convex polygon has n(n-3)/2 diagonals.
This polygon has 14 diagonals.
i.e., n(n-3)/2 = 14
Or n(n-3) = 28
Solving for n, we get n = 7.
So, the given polygon has 7 sides.
You can access sample practice questions on Geometry for your GMAT Prep by clicking here
Follow us on http://twitter.com/4GMAT
Labels: Diagonals, GMAT Geometry, GMAT Problem Solving, Polygons